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Truncated cuboctahedron
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The truncated cuboctahedron is an Archimedean solid. It has 12 square faces, 8 regular hexagonal faces, 6 regular octagonal faces, 48 vertices and 72 edges. Since each of its faces has point symmetry (equivalently, 180° rotational symmetry), the truncated cuboctahedron is a zonohedron.
rnate interchangeable names are:
The name truncated cuboctahedron, given originally by Johannes Kepler, is a little misleading.

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Encyclopedia
The truncated cuboctahedron is an Archimedean solid. It has 12 square faces, 8 regular hexagonal faces, 6 regular octagonal faces, 48 vertices and 72 edges. Since each of its faces has point symmetry (equivalently, 180° rotational symmetry), the truncated cuboctahedron is a zonohedron.
Other names
Alternate interchangeable names are:
- Rhombitruncated cuboctahedron
- Great rhombicuboctahedron
- Omnitruncated cuboctahedron
The name truncated cuboctahedron, given originally by Johannes Kepler, is a little misleading. If you truncate a cuboctahedron by cutting the corners off, you do not get this uniform figure: some of the faces will be rectangles. However, the resulting figure is topologically equivalent to a truncated cuboctahedron and can always be deformed until the faces are regular.
The alternative name great rhombicuboctahedron refers to the fact that the 12 square faces lie in the same planes as the 12 faces of the rhombic dodecahedron which is dual to the cuboctahedron. Compare to small rhombicuboctahedron.
One unfortunate point of confusion: There is a nonconvex uniform polyhedron by the same name. See uniform great rhombicuboctahedron.
Area and volume
The area A and the volume V of the truncated cuboctahedron of edge length a are:
Vertices
To derive the number of vertices, we note that each vertex is the meeting point of a square, hexagon, and octagon.
- Each of the 12 squares with their 4 vertices contribute 48 vertices because .
- Each of the 8 hexagons with their 6 vertices contribute 48 vertices because .
- Each of the 6 octagons with their 8 vertices contribute 48 vertices because .
Therefore, there may seem to exist vertices. However, we have over-counted the vertices thrice since a square, hexagon, and octagon meet at each vertex. Consequently, we divide 144 by 3 to correct for our over-counting: .
Cartesian coordinates
The Cartesian coordinates for the vertices of a truncated cuboctahedron having edge length 2 and centered at the origin are all permutations of:
- (±1, ±(1+v2), ±(1+v8))
See also
External links
- The Encyclopedia of Polyhedra
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