Algebraically closed group
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In mathematics
Mathematics
Mathematics is the study of quantity, space, structure, and change. Mathematicians seek out patterns and formulate new conjectures. Mathematicians resolve the truth or falsity of conjectures by mathematical proofs, which are arguments sufficient to convince other mathematicians of their validity...

, in the realm of group theory
Group theory
In mathematics and abstract algebra, group theory studies the algebraic structures known as groups.The concept of a group is central to abstract algebra: other well-known algebraic structures, such as rings, fields, and vector spaces can all be seen as groups endowed with additional operations and...

, a group
Group (mathematics)
In mathematics, a group is an algebraic structure consisting of a set together with an operation that combines any two of its elements to form a third element. To qualify as a group, the set and the operation must satisfy a few conditions called group axioms, namely closure, associativity, identity...

  is algebraically closed if any finite set of equations and inequations that "make sense" in already have a solution in . This idea will be made precise later in the article.

Informal discussion

Suppose we wished to find an element of a group satisfying the conditions (equations and inequations):


Then it is easy to see that this is impossible because the first two equations imply . In this case we say the set of conditions are inconsistent with . (In fact this set of conditions are inconsistent with any group whatsoever.)




Now suppose is the group with the multiplication table:

Then the conditions:


have a solution in , namely .

However the conditions:


Do not have a solution in , as can easily be checked.




However if we extend the group to the group with multiplication table:

Then the conditions have two solutions, namely and .

Thus there are three possibilities regarding such conditions:
  • They may be inconsistent with and have no solution in any extension of .
  • They may have a solution in .
  • They may have no solution in but nevertheless have a solution in some extension of .


It is reasonable to ask whether there are any groups such that whenever a set of conditions like these have a solution at all, they have a solution in itself? The answer turns out to be "yes", and we call such groups algebraically closed groups.

Formal definition of an algebraically closed group

We first need some preliminary ideas.

If is a group and is the free group
Free group
In mathematics, a group G is called free if there is a subset S of G such that any element of G can be written in one and only one way as a product of finitely many elements of S and their inverses...

 on countably many generators, then by a finite set of equations and inequations with coefficients in we mean a pair of subsets and of the free product
Free product
In mathematics, specifically group theory, the free product is an operation that takes two groups G and H and constructs a new group G ∗ H. The result contains both G and H as subgroups, is generated by the elements of these subgroups, and is the “most general” group having these properties...

 of and .

This formalizes the notion of a set of equations and inequations consisting of variables and elements of . The set represents equations like:

The set represents inequations like


By a solution in to this finite set of equations and inequations, we mean a homomorphism , such that for all and for all . Where is the unique homomorphism that equals on and is the identity on .

This formalizes the idea of substituting elements of for the variables to get true identities and inidentities. In the example the substitutions and yield:


We say the finite set of equations and inequations is consistent with if we can solve them in a "bigger" group . More formally:

The equations and inequations are consistent with if there is a group and an embedding such that the finite set of equations and inequations and has a solution in . Where is the unique homomorphism that equals on and is the identity on .

Now we formally define the group to be algebraically closed if every finite set of equations and inequations that has coefficients in and is consistent with has a solution in .

Known Results

It is difficult to give concrete examples of algebraically closed groups as the following results indicate:
  • Every countable group can be embedded in a countable algebraically closed group.
  • Every algebraically closed group is simple
    Simple group
    In mathematics, a simple group is a nontrivial group whose only normal subgroups are the trivial group and the group itself. A group that is not simple can be broken into two smaller groups, a normal subgroup and the quotient group, and the process can be repeated...

    .
  • No algebraically closed group is finitely generated
    Finitely generated
    In mathematics, finitely generated may refer to:* Finitely generated group* Finitely generated monoid* Finitely generated abelian group* Finitely generated module* Finitely generated ideal* Finitely generated algebra* Finitely generated space...

    .
  • An algebraically closed group cannot be recursively presented
    Presentation of a group
    In mathematics, one method of defining a group is by a presentation. One specifies a set S of generators so that every element of the group can be written as a product of powers of some of these generators, and a set R of relations among those generators...

    .
  • A finitely generated group has solvable word problem
    Word problem for groups
    In mathematics, especially in the area of abstract algebra known as combinatorial group theory, the word problem for a finitely generated group G is the algorithmic problem of deciding whether two words in the generators represent the same element...

    if and only if it can embedded in every algebraically closed group.


The proofs of these results are, in general very complex. However a sketch of the proof that a countable group can be embedded in an algebraically closed group follows.

First we embed in a countable group with the property that every finite set of equations with coefficients in that is consistent in has a solution in as follows:

There are only countably many finite sets of equations and inequations with coefficients in . Fix an enumeration of them. Define groups inductively by:



Now let:


Now iterate this construction to get a sequence of groups and let:


Then is a countable group containing . It is algebraically closed because any finite set of equations and inequations that is consistent with must have coefficients in some and so must have a solution in .
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